Répondre :

bonjour,

fonction affine  =ax+b
f(2) = 5⇒2a+b = 5
f(-3) =-10⇒-3a+b  =-10

2a+b = 5
-3a+b = -10

-1(2a+b) =5
-3a+b = -10

-2a-b = -5
-3a+b = -10
-5a  =-15
a = 3

2a+b = 5
6+b = 5
b = -1

f(x) = 3x-1

D'autres questions